iz^4-(2+4i)z^2-i=0

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Solution for iz^4-(2+4i)z^2-i=0 equation:


Simplifying
iz4 + -1(2 + 4i) * z2 + -1i = 0

Reorder the terms for easier multiplication:
iz4 + -1z2(2 + 4i) + -1i = 0
iz4 + (2 * -1z2 + 4i * -1z2) + -1i = 0

Reorder the terms:
iz4 + (-4iz2 + -2z2) + -1i = 0
iz4 + (-4iz2 + -2z2) + -1i = 0

Reorder the terms:
-1i + -4iz2 + iz4 + -2z2 = 0

Solving
-1i + -4iz2 + iz4 + -2z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2z2' to each side of the equation.
-1i + -4iz2 + iz4 + -2z2 + 2z2 = 0 + 2z2

Combine like terms: -2z2 + 2z2 = 0
-1i + -4iz2 + iz4 + 0 = 0 + 2z2
-1i + -4iz2 + iz4 = 0 + 2z2
Remove the zero:
-1i + -4iz2 + iz4 = 2z2

Combine like terms: 2z2 + -2z2 = 0
-1i + -4iz2 + iz4 + -2z2 = 0

The solution to this equation could not be determined.

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